| Author | Ian - Tutorial Posts = 62 |
| Pointers are pointers to memory, the variable that is defined as a pointer still holds the same area in memory as the type of the pointer e.g. char and int are of different size in memory, just do a cout << sizeof(char) << “ “ << sizeof(int); to find out. The actually pointer holds the address of the variable it is pointing to, e.g. The value variable Value = 10, address within the memory for value = 4 The pointer ValuePointer = 4 (the address of the value), address within the memory = 200 The valuepointer actually equals 4, the memory of the value variable, if you use the * (pointer) then you will get the value pointed to, 10, and if you use the & (address) you will get 200 which is the place in memory where the valuepointer is placed in memory. For example int main() { int value1 = 10; int *valp = &value1; // equals the memory address of value1 std::cout << "Value 1 = " << value1 << " address = " << &value1 << "\n"; std::cout << "Value p = " << *valp << " address = " << &valp << " pointed to memory " << valp << "\n"; std::cout << "The value p pointerd to memory is the same as the memory address as value 1\n"; std::cout << "The value p = the pointerd memory value that is assoicated with the value that is in valp (address of memory)\n"; (*valp)++; // correct increament the value that is pointed to by the address held by vapl std::cout << "Value 1 = " << value1 << " address = " << &value1 << "\n"; std::cout << "Value p = " << *valp << " address = " << &valp << " pointed to memory " << valp << "\n"; *valp++; // incorrect will increament the address that is held valp by sizeof(int) (usually 4) std::cout << "Value 1 = " << value1 << " address = " << &value1 << "\n"; std::cout << "Value p = " << *valp << " address = " << &valp << " pointed to memory " << valp << "\n"; return 0; } |
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